Need help with question 43 part A 43 A plan for an executive
Solution
A.
Formulating the null and alternatuve hypotheses,          
           
 Ho:   p   =   0.05
 Ha:   p   =/=   0.05
 As we see, the hypothesized po =   0.05      
 Getting the point estimate of p, p^,          
           
 p^ = x / n =    0.08      
           
 Getting the standard error of p^, sp,          
           
 sp = sqrt[po (1 - po)/n] =    0.009746794      
           
 Getting the z statistic,          
           
 z = (p^ - po)/sp =    3.077935056      
           
 As this is a    2   tailed test, then, getting the p value,  
           
 p =    0.001042202      
 significance level =    0.01      
 Comparing p and the significance value, we   REJECT THE NULL HYPOTHESIS.      
Thus, there is sufficient evidence that the proportion of those who qualify is not 5% (it is actually greater than that).
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