Axis of symmetry and vertex of the parabola fx x2 2x 3 ar
     Axis of symmetry and vertex of the parabola f(x) = -x^2 - 2x + 3 are  a. Vertex =(-1, 4) and Axis of symmetry, line x = -1  b. Vertex =(-1, 4) and Axis of symmetry, line y = -1  c. Vertex =(-1, 4) and Axis of symmetry: line y = 4  d. Vertex = (-1, 4) and Axis of symmetry: line x = 1  e. Vertex = (4, -1) and Axis of symmetry: line x = -1 
  
  Solution
f(x)= -x2-2x+3
vertex x=-b/2a= -(-2)/- 2=-1
f(-1)= -1+2+3=4
vertex= (-1,4)
axis of symmetry
x+1=0
x=-1
correct option is a

