The perihelion distances to Pluto is 445 Times 108 km and ap

The perihelion distances to Pluto is 4.45 Times 10^8 km and aphelion is 7.37 Times 10^10 km., find the eccentricity.

we have an equation rp / ra = (1-e)/(1+e)

where e is eccentricity

rp is perihelion distance and ra is aphelion distance

from this we can find e

0.6038*10^-2 KM = (1-e)/(1+e)

0.006038 KM = (1-e)(1-e)/(1+e)(1-e)

0.006038 KM = 1+e^2-2e/(1-e^2)

0.006038 -0.006038 e^2 = 1+e^2-2e

1.006038 e^2 - 2e +(1-0.006038) =0

from here we can find out eccentricity