Find the equation for each line in slope intercept form ymxb

Find the equation for each line in slope intercept form y=mx+b. Through (5,7) and (10,11) 1 to integral(x)=-1/5x+1, through _-2,-1) Use the graphs of f and g to determine the following. Domain(f): [-2,5] Range(f):[3,-3] Function (f):YES/NO (f-g)(0) (f-g)(-1)

Solution

2. a) ( 5, 7) and ( 10, 11)

slope = ( 11-7)/( 10 -5) = 4/-5 = - 4/5

std slope intercept form : y = mx +c

7 = 5(-4/5) +c ----> c = 11

y = -4x/5 +11 (Equation of line)

b) perpendicular to f(x) = -x/5 +1

slope = -1/5

slope of line perpendicular = 5

y = 5x +c . Find c using ( -2,-1)

-1 = 5*(-2) +c ---> c = -1 +10 =9

y = 5x +9

3. a) Domain of f(x): [ -2 , 5]

Range of f(x) : [ -3 , 3]

b) ( f- g)(0) = f(0) -g(0) = 3 - (-2) = 5

c) (f .g)(-1) = f(-1).g(-1) =2*3 =6