Find the vertex of parabola fx6x212x78SolutionThe coordinate

Find the vertex of parabola f(x)=6x^2+12x+78?

The coordinates of the vertex of the parabola are:

V(-b/2a ; -delta/4a)

a,b,c are the coefficients of the quadratic:

y = ax^2 + bx + c

Comparing, we\'ll get the values of the coefficients:

a = 6, b = 12 , c = 78

We\'ll determine the x coordinate of the vertex:

xV = -b/2a

xV = -12/12

xV = -1

We\'ll determine the y coordinate of the vertex:

yV = -delta/4a

delta = b^2 - 4ac

delta = 144 - 4*6*78

delta = 144 - 1872

yV = -(-1728)/24

yV = 72

The coordinates of the vertex of the parabola are: V(-1, 72).