Determine the intervals of the domain over which each functi
Solution
we would see for any breaks in the graph
11. contious over the entire domain ( -inf , inf)
12 contious over the entire domain ( -inf , inf)
13 continous over the domain [3, inf)
14 continous over the domain (-inf , -1]
15 discontinous at x = 3
So, continous over the interval ( -inf , 3) U( 3, inf)
16 discontinous at x = 1
So, continous over the interval ( -inf , 1) U( 1, inf)
