Solve for v2 and phi m11cos51 m2v2cosphi 04 m1 02 m2 03S

Solve for v2 and phi:

m1*1[cos(51]) + m2*v2[cos(phi]) = 0.4

m1 = 0.2

m2 = 0.3

Solution

Solve for v2 and phi:

m1*1[cos(51]) + m2*v2[cos(phi]) = 0.4

m1 = 0.2, m2 = 0.3

Answer....

m1*1[cos(51]) + m2*v2[cos(phi]) = 0.4

put m1 and m2 values in the above equation

0.2*1[cos(51]) + 0.3*v2[cos(phi]) = 0.4

2cos(51)+3v2cos(phi) = 4

This can be written as

2cos(51)+3*v2*cos(phi) - 4 = 0

2*0.7421+3*v2*cos(phi) - 4 = 0

1.484+3*v2*cos(phi) - 4 = 0

3*v2*cos(phi) - 2.515 = 0

v2*cos(phi) - 0.8385 = 0

This is a non linear function, so a solution using MATLAB can be taken which involves the solver fsolve

v2 and phi are unknowns and there is only equation to solve, so with the initial guess trial and error is taken up to find both

MATLAB code:

%function file chegg1.m

function F = chegg1(x)
v2 = x(1);
phi = x(2);
F = [v2*cos(phi) - 0.8385]

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%Script file

clc
clear all
xinit = [0.5,90]
[x, fval] = fsolve (\'chegg1\',xinit)

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Answer

x = 1.063259491176315 88.626840985937108

which shows v2 and phi that is

v2 = 1.063259491176315 and phi = 88.626840985937108

for which the function value is

fval =     3.786970736996409e-013