A qualitycontrol manager at a large manufacturing company wi

A quality-control manager at a large manufacturing company will like to measure his employees’ knowledge of total quality management. A quality awareness test is administered to a random sample of 6 employees at each of 3 plants in Atlanta, Dallas and Seattle. The test scores are shown below:

Atlanta

Dallas

Seattle

85

71

59

75

75

64

82

73

62

76

74

69

71

69

75

85

82

67

At = 0.05, is there sufficient evidence that the employees’ knowledge of total quality management differs among the three plants?

Question: True or false: Ho: µ(atl) = µ(dallas)= µ(seattle)

True

False

4 points

Question 2

True or false: SSG (between groups) = 520

True

False

4 points

Question 3

True or false: SSTotal = 946

True

False

4 points

Question 4

DFE (degrees of freedom within groups) = 17

True

False

4 points

Question 5

True or false: MSG (between groups) = 258

True

False

4 points

Question 6

True or false: MSE (within groups) = 30.67

True

False

4 points

Question 7

True or false: F test statistic = 9.0

True

False

4 points

Question 8

True or false: p-value = 0.0027

True

False

4 points

Question 9

True or false: At = 0.05, reject Ho. Employees’ knowledge of total quality management differs among the three plants.

True

False

Atlanta	Dallas	Seattle
85	71	59
75	75	64
82	73	62
76	74	69
71	69	75
85	82	67

Solution

Using technology (like Excel below, in Data-->Data Analysis-->Anova Single Factor), we have the summary:

Thus,

1. TRUE

2. FALSE (it is 516)

3. TRUE

4. FALSE

5. TRUE

6. FALSE. It is 28.666667.

7. TRUE.

8. TRUE.

9. TRUE. it is because P < 0.05.

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
Column 1	6	474	79	34
Column 2	6	444	74	20
Column 3	6	396	66	32
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	516	2	258	9	0.002703	3.68232
Within Groups	430	15	28.66667
Total	946	17