Bowl 1 contains 2 grape candies 7 lemon candies 8 cherry can

Bowl #1 contains 2 grape candies, 7 lemon candies, 8 cherry candies and 3 raspberry candies.

Bowl #2 contains 7 grape candies, 8 lemon candies, 2 cherry candies and 3 raspberry candies.

What is the probability that the first selected candy is lemon or that the second selected candy is cherry?

Could you please explain your answer too. THanks!

Solution

Bowl #1 contains 2 grape candies, 7 lemon candies, 8 cherry candies and 3 raspberry candies.

Bowl #2 contains 7 grape candies, 8 lemon candies, 2 cherry candies and 3 raspberry candies.

What is the probability that the first selected candy is lemon or that the second selected candy is cherry?

Total candies in bowl #1 =20

Lemon candies in bowl #1 =7

P( selecting lemon from bowl #1) =7/20

Total candies in bowl #2 =20

cherry candies in bowl #2 =2

P( selecting cherry from bowl #2) =2/20

probability that the first selected candy is lemon from bowl #1 or that the second selected candy is cherry from bowl #2

=7/20 + 2/20

= 9/20

=0.45