Im not looking for an entire solution to this problem Im loo

I\'m not looking for an entire solution to this problem. I\'m looking for how to approach, what kind of steps needs to be taken, etc. Some sort of explanation that can get me started on the project.

The Clean Petroleum Company (CPC) is interested in reducing pollution in the atmosphere. When people overfill their gas tanks gas is spilled and evaporates causing air pollution. To minimize this problem, their pumps currently turn off when the back pressure from the gas tank gets too large while the nozzle handle switch is activated (i.e., compressed). They have asked you to design a controller that does the following: If the nozzle handle switch is depressed and the pump pressure sensor indicates low pressure, then allow gas to be pumped. If the pump pressure sensor indicates high pressure then turn-off the pump. (The system clock pulses every one second and you may assume that once the pump shuts off, the pump pressure returns to normal within one second.) Once the pressure returns to normal, allow the pump to be controlled again by the nozzle handle switch. If the pump pressure sensor indicates high pressure a second time, your design will permanently shut down the pump until reset by gas station personnel. (Note that there are two inputs to your synchronous machine: the nozzle handle switch position, and the pump pressure sensor indicator. Your synchronous machine has one output that controls the pump.) All information to complete this design may not be specified. Write down and report any assumptions that you make in your design. Be sure to use debounced “logic switches” for driving the clock input to the flip-flops

Solution

The main thing in this project is how good is the feedback circuit that we opt to.

Using Flip Flops and counters together will get good results, as we have to control the system baseing on the number of times the pump pressure sensor indicates high pressure.

We can use a Mod 2 counter ( A mod 2 counter will reset after 2 clock pulses. Note that the clock of the counter is controlled using pressure sensor output but not the clock which is given as input to the FlipFlop). That means that the counter will reset after the pressure sensor produces high output for the second time.

As soon as the counter is reset , the whole system is turned off.

The main point is about the operation of this counter synchronously with the flip-flop. The output frequency of a mod 2 counter is input frquency/2.

The clock might be an edge triggered one and the flip flop that can be used is JK Flip-flop( considering J as nozzle and K as pressure sensor output).

I\'m not looking for an entire solution to this problem. I\'m looking for how to approach, what kind of steps needs to be taken, etc. Some sort of explanation t

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