Find the margin of error for the given values of c s and n c

Find the margin of error for the given values of c, s, and n.

c=0.90
s=3.7
n=22

Solution

Note that              
Margin of Error E = t(alpha/2) * s / sqrt(n)              
      
              
where              
alpha/2 = (1 - confidence level)/2 =    0.05          
t(alpha/2) = critical t for the confidence interval =    1.720742903          
s = sample standard deviation =    3.7          
n = sample size =    22          
df = n - 1 =    21          

Thus,              

Margin of Error E =    1.357395392   [ANSWER]