Two genes A C are located 30 map units apart Given 1000 pro

Two genes, A & C, are located 30 map units apart. Given 1000 progeny, indicate the expected number of progeny from the following cross.

A   c                X                     a   C

A   c

____                X                     a c

a    C

Solution

30 map units means 30% recombination

So 70% of the progeny are parental and 30% of the progeny are recombinants

For the cross, A c X a C the following are the expected progeny,

Ac - 35% = 350 out of 1000

aC - 35% = 350 out of 1000

AC - 15% = 150 out of 1000

ac - 15 % = 150 out of 1000

For the cross, Ac X ac

the following are the expected progeny,

Ac = 35% = 350

ac = 35% = 350

AC = 15% = 150

aC = 15% = 150