If there were 100 proteins in a cube with volume 106 nm3 the

If there were 100 proteins in a cube with volume 10^6 nm^3 then what is the concentration of protein (in molarity)?

100 proteins in 10⁶ nm³ or 10^-9nL

1 molar solution= 1 mol /liter

=> 1 molar solution= 6.023 x 10²³ molecules /liter

=> 1 molar solution= 6.023 x 10²³ molecules /10⁹nL

=> 1 molar solution= 6.023 x 10^23-09 molecules /nL

=> 1 molar solution= 6.023 x 10^23-18 molecules / 10^-9nL

We have 100 molecules in 10^-9nL

So molarity becomes

602300/100

The concentration of protein=6023 molar