A survey of 250 households showed 53 owned at least one snow

A survey of 250 households showed 53 owned at least one snow blower. Find a point estimate for p, the population proportion of households that own at least one snow blower. 0.788 0.269 0.175 0.212 95% confidence interval; n = 91 ; x bar = 13, s = 9.4 3.73 1.31 1.53 1.38 A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 230 milligrams with s = 13.8 milligrams. Construct a 95 percent confidence interval for the true mean cholesterol content of all such eggs. 222.8

Solution

5. The population proportion of household own at leat one snow blower =53/250=0.212

Ans=(d)

6. Margin of error is the radius of the confidence interval for a particular statistics. It is calculated as 1.96*standarde deviation/sqrt(n). But herrs=9.4 and n=91. I can not find the answer from your question.

If \"s\" is standard deviation than margin of error = 1.96*9.4/sqrt(91)=1.9313.

7. n=12, mean(x_)=230, s=13.8 and the t-value for 0.05 level of significance , n=91 at two tail is 2.1788.

Therefore, the confidence interval is (x_)+/-(t*s/sqrt(n))= 230+/-2.1788*13.8/(sqrt(12) = 230+/-8.679= (221.320, 238.6798)

Ans: (d)

8. Ans (c)