The force of impact to break a particular brand of wooden ba
The force of impact to break a particular brand of wooden baseball bat is normally distributed with a mean of 5000 pounds and a standard deviation of 2000 pounds. What proportion of this brand of baseball bat breaks at less than 1500 pounds of force?
0.0401
0.9599
0.6834
0.9500
0.000
| 0.0401 | ||
| 0.9599 | ||
| 0.6834 | ||
| 0.9500 | ||
| 0.000 |
Solution
So proportion of this brand of baseball bat breaks at less than 1500 pounds of force is
P(X<1500) = P((X-mean)/s <(1500-5000)/2000)
=P(Z<-1.75) = 0.0401 (from standard normal table)
Answer: 0.0401
