Need help finding CPI for 1996 and 2002 Fall 2016 Math 151 H
Solution
1)
The equation of line will be of the form
y = mx + C
x = 0 corresponds to the year 1990
y(0) = m(0) + C = C = 142.2
Since x=0 corresponds to year 1990, hence x=10 will correspond to year 2000
y(2000-1990) = m(10) + C = 192.2
10m + C = 192.2
10m = 50
m = 5
Hence the equation of line will be
y = 5x + 142.2
year 1992 corresponds to the value of x=2
y = 5(2) + 142.2 = 152.2
year 2003 corresponds to the value of x=13
y = 5(13) + 142.2 = 207.2
2)
The equation of line will be of the form
y = mx + C
x = 0 corresponds to the year 1990
y(0) = m(0) + C = C = 114.3
Since x=0 corresponds to year 1990, hence x=10 will correspond to year 2000
y(2000-1990) = m(10) + C = 154.3
10m + C = 154.3
10m = 40
m = 4
Hence the equation of line will be
y = 4x + 114.3
year 1996 corresponds to the value of x=6
y(1996) = 4(6) + 114.3 = 138.3

