HELP POINTS WILL BE GIVEN SHOW ALL THE WORK THANKS The circu

HELP!! POINTS WILL BE GIVEN!! SHOW ALL THE WORK, THANKS.

The circuit below is in steady state

A. Calculate the voltage across the capacitor V_c and the current through the inductor i_L

B. Calculate the energy stored in the capacitor.

C. Calculate the energy stored in the inductor.

consider f=60 hertz

Xl=j2*3.14*60*2=j753.6 ohms

Xc=1/(j2*3.14*60*0.1)=-j0.02652 ohms

apply nodal analysis

(v-24)/(4*10^3)+v/(6*10^3-j0.02652)+v/(2*10^3+j753.6)=0

solving the above equation, we get

v=6.8943<10.92 volts

current flown through the inductor is Il=v/(2*10^3+j753.6)=3.225*10^-3<-9.719 amps

current flown through the capacitor is Ic=v/(6*10^3-j0.02652)=1.149*10^-3<10.92 amps

voltage across the capacitor is Vc=Ic*Xc=3.047*10^-5<-79 volts

energy stored in the capacitor is E=(1/2)*C*V^2=0.5*0.1*(3.047*10^-5<-79)^2=4.642*10^-11<-158 JOULES

ENERGY STORED IN THE INDUCTOR IS E=(1/2)*L*Il^2=0.5*2*(3.225*10^-3<-9.719)^2=1.04*10^-5<-19.438 JOULES.