Determine the number of moles of oxygen gas in the following

Determine the number of moles of oxygen gas in the following container.

The container holds 0.48 m³ at 68.6^oF and an a gauge pressure of 41.46kPa.

Solution

Volume V = 0.48 m ³

Temprature F = 68.6 ^o F

We know relation between kelvin scale temprature K and fharenheit scale temprature F is

      (K-273)/100 = (F-32)/180

      (K-273)/100 = (68.6-32)/180

                        = 0.203333

             K -273 = 20.333

                    K = 293.33 kelvin

Gauge pressure = 41.46 kPa

Pressure of the gas P = atmosphere pressure + gauge pressure

                                = 101 kPa +41.46 kPa

                                = 142.46 kPa

                                 = 142.46 x10 ³ Pa

From the relation PV = nRT

From this number of moles n = PV/RT

                                          =(142.46 x10 ³)(0.48)/(8.314)(293.33)

                                          = 28.04 mol