A landscaper plants circular flowerbeds in square plots of v

A landscaper plants circular flowerbeds in square plots of various sizes. After planting flowers (shaded region shown), grass is put down to form a lawn in the remaining area of the square (while regions). Complete the following table.

Solution

length of sides of each side is x

so radius would be x/2

for x = 1 , radius = 1/2 feet

area of square plot = 1^2 = 1 sq feet

area of circular flower beds = pi*r^2 = 3.14(1/2)^2 = .785 sq feet

area of grass = area of square - area of circularr flower bed = .215 sq feet

2) x = 2

radius = 2/2 = 1

area of square = 2^2 = 4 sq feet

area of circular floiwer bed = 3.14 ( 2/2)^2 = 3.14 sq feet

area of grass = 4 - 3.14 = .86 sq feet

3) x = 3.5

radius = 3.5 / 2 = 1.75 feet

area of square = 3.5^2 = 12.25 sq feet

area of circular flower bed = 3.14 (1.75)^2 = 9.616 sq feet

area of grass = 12.25 - 9.616 = 2.634 sq feet