Find a positive root of the cubic equation x35x70 using Card

Find a positive root of the cubic equation

x3+5x-7=0

using Cardan-Tartaglia method.

Solution

We are given the equation x3 + 5x - 7 = 0

Using the Cardan Tartaglia method, the solution to the equation x3+ ax2+ bx + c = 0 can be found as under:

Let x = u + v . Then this equation changes to u3 + v3 + (u + v)(3uv + p) + q = 0

where p = b – (a2 /3) = 5 ( as a = 0 and b = 5) and q = c + (2a3 – 9ab)/ 27 = - 7 ( as a = 0 , b = 5 and c = - 7)

The solutions are    u3 = (-q/2) + v(q2 /4) + (p3 /27) = 7/2 + v ( 49/4) + 125/27 and

v3 = (-q/2) - v(q2 /4) + (p3 /27) = 7/2 – v ( 49/4) + 125/27

Since 27q2 + 4p3 = 27 (49) + 4 (125) = 1323 + 500 = 1823 which is > 0, the roots will be real.

We can find the cube roots of these equations to solve for u and v, by using the following formulae:

(a + b)3 = a3 + 3a2b + 3ab2 + b3   

(a - b)3 = a3 - 3a2b + 3 ab2 - b3  

Then the solution is x = u + v.

Find a positive root of the cubic equation x3+5x-7=0 using Cardan-Tartaglia method.SolutionWe are given the equation x3 + 5x - 7 = 0 Using the Cardan Tartaglia

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