Find each limit in problem 34 and 36 34 lim x 0 ln1x1x 36 li

Solution

34. lim x -->0 ln(1+x)/(1+x) ln(1+x)/(1+x) = ln(1)/(1) = 0 36. lim x -->0 (e^x + e^-x -2 )/ x^2 we can use l hospitals rule if limit is in 0/0 form differentiating e^x - e^-x /(2x) again e^x + e^-x /2 now x-->0 limit --> 1 + 1 /2 = 1