Compute the energy resulting from 92 U 235 0 n1 56 Ba138

Compute the energy resulting from 92 U ^235 + 0 n^1 > 56 Ba^138 + 36 Kr^96 + 2 0n^1

Solution

Mass of 92 U 235 is M = 235.0439299 amu

Mass of neutron M \' = 1.0086649156 amu

Mass of of 56 Ba 138 is m = 137.9052472 amu

Mass of 36 Kr 96 is m \' = 95.94307 amu

Mass defect dm = ( M+M\') -(m+m \' +2M\')

                        = 236.0525948 amu - 235.865647 amu

                        = 0.18694777 amu

We know 1 amu = 931.5 MeV

So, Required energy E = dm x 931.5MeV

                                  = 174.14 MeV