Squareroot 2 cos 3x1 0 0 2 pi for decimalSolutionsqrt2cos3x

Squareroot 2 cos 3x-1 = 0 [0, 2 pi] for decimal

Solution

sqrt2cos3x -1 =0

cos3x = 1/sqrt2

3x = cos^-1(1/sqrt2)

general solution:

3x = pi/4+2kpi , 3pi/4 +2kpi

x = (pi+6k*pi)/12 , (3pi + 6kpi)/12 where k is an integer ; k=0, 1 , 2 ..

Between [ 0, 2pi]

k =0 ; x= pi/12 , pi/4

k =1 ; x =7pi/12 ,3pi/4

k =2 ; x= 13pi/12 , 5pi/4

k = 3; x = 19pi/12 , 7pi/4