What is its average velocity during this time interval answe

What is its average velocity during this time interval? answer in units of m/s.

Solution

We pressume that the velocity of the wrench while hitting the ground is v and the initial velocity u. Since the worker has drpped the wrench its initial velocity u=0.

We know that v^2- u^2 = 2*g* s, where g is the acceleration due to gravity and s is the vertical distance the wrench trvaresed . Therfore, s=85.9 m

Substituting the values we get:

v^2-0^2=2*9.8*85.9

v= sqrt(2*9.8*85.9)= 41.03m/s