Identify the value of x after the third iteration that maxim
Identify the value of x after the third iteration that maximizes the function f(x) = –1.5x6 – 2x4 + 12x using Newton\'s method for the given initial condition x0 = 2.
Here are the options:
1.047716
0.91692
0.81243
1.26462
Solution
Solution : The value of x after the third iteration is 0.91692
| n | x | accuracy(x) | f(x) | 
| 1 | 1.999492514992194975634 | 1.999 | -961 | 
| 2 | 1.998985106780896009731 | 1.999 | -959.6371904777035155496 | 
| 3 | 1.998477775353656159683 | 1.998 | -958.2761911902669896665 | 
| 4 | 1.997970520698042607179 | 1.998 | -956.9169998492661991168 | 

