For a normal distribution with mean 200 and standard deviat

For a normal distribution with mean = 200 and standard deviation = 50, find the following values:

What is the probability of randomly selecting a score greater than X = 235

Solution

Normal Distribution
Mean ( u ) =200
Standard Deviation ( sd )=50
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P(X > 235) = (235-200)/50
= 35/50 = 0.7
= P ( Z >0.7) From Standard Normal Table
= 0.242