The solutions in the two and of this Ulube are separated by

The solutions in the two and of this U-lube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with an aqueous solution of 2 mols of sucrose and 1 mol of glucose. Side B is half-tilled with an aqueous solution of 1 mol of sucrose and 2 mols of glucose. Initially, the liquid levels on both sides are equal. Initially (before any diffusion takes place), what is the tonicity of side A with respect to (compared to) side B? Isotonic Hypertonic Hypotonic After diffusion and equilibrium: _____ How many mols of sucrose are on side A? _____ side B? _____ How many mols of glucose are on side A?_____ side B? After diffusion what would you observe in the water level in side A? an increase in the water level. no change in the water level a decrease in the water level

Solution

A. A isotonic

As both the sides of tube have equal moles of solute dissolved, so they become isotonic.

B. As the membrane is impermiable to sucrose, so no movement of sucrose can take place hence they will remain same, 2 moles in A and 1 mole in B.

Now though membrane is permiable to glucose and water but to maintain the isotonicity no net movement of glucose will take place, so 1 mole in A and 2 moles in B

C. B

There will be no change in the water levels as the solutions on both the arms A and B are isotonic so no net movement of water takes place