An intermediate data called dct 110 needs to be scaled down

An intermediate data called \'dct [11;0]\' needs to be scaled down by 8. For example, if dct - 180, then the scaled output called \'dctq\' is 160. Complete the following Verilog code for implementation the scaling. write a test bench and include your simulation results. module a5_9 (dct, dctq); input [11;.]dct; output [8;0]dctq; wire [8;0]dctq; assign dctq =://data/8 endmodule

Solution

To scale by 8 bits, we need to shift the input by 3 powers of 2.

The code is below:-

module a5_9(dct,dctq);
input [11:0] dct;
output [8:0} dctq;
wire [8:0] dctq;
assign dctq = input >> 3; // This will scale the data by 8.
endmodule