A SOLVE continued What is the Pvalue for the test A 044 B 05

Solution

0.11

P-value. (Using Table A) 2P(Z ? |z ? |) = 2P(Z ? | ? 0.40|) = 2P(Z ? 0.40) = 2(1 ? 0.6554) = 2(0.3446) = 0.6892

We reject the null hypothesis and conclude the conductivity is different from 10.1.

. This sample gives little reason to doubt that the true conductivity is 10.1. That is, there is virtually no evidence that the true conductivity of the rod differs from 10.1. Random chance easily explains the observed sample mean.