22 mLABCe l 27 Find m DAB mLBCD and m LCDA to the nearest de

22. mLABC-e l 27\". Find m DAB, mLBCD, and m LCDA to the nearest degree. mLCDA

Solution

If BD has to be perpendicular to AC, then the product of the slopes shoul be = -1

Slope of a line = (y2 - y1)/x2 - x1)

For line AC [A = (0,0) and C = (4,8)] the slope m1 = (8-0)/(4-0) = 8/4 = 2

For Line BD [B = (0,5) and D = (10,0)] the slope m2 = (0-5)/(10-0) = -5/10 = -1/2

The product of the slopes m1 x m2 = 2 x -1/2 = -1, therefore TRUE, Line AC is perpendicular to line BD.