Number 8 Number 14 and Number 16 Determine whether or not th
Solution
excercise 1 to 6 of solution
for pythagorean triple
this condition is satisfied then we can say that given example is pythagorean triple
a^2+b^2=c^2
problem 1. 10,24,26
here a=10 b=24 and c=26 put all this in equation a^2+b^2=c^2
10^2+24^2=26^2
we got 100+576=676
that means 676=676
means it is satisfied the pythagorean triple like that
similary we have check then problem no. 1, 4 and 6 is pythagorean triple or proble no 2,3 and 5 is not a pythgorean triple.
problem no. 7 ans-problem no. 1, 4 and 6 is pythagorean triple because
this condition is satisfied then we can say that given example is pythagorean triple
a^2+b^2=c^2.
solution of prolem 8 to 12
8. 27,36,45
we know that for pythagorean triple
27^2+36^2=35^2
729+1296=2025
2025=2025
it is the traingle similar to pythgorean triple
9.45,24,51
45^2+24^=51^2
2601=2601
it is also
10.350,120,370
350^2+120^2=370^2
136900=136900
it is also
11.126.120,174
126^2+120^2=174^2
30276=30276
it is also..
12.135,72,153
135^2+72^2=153^2
23409=23409
it is also.
now 13 to 18
13.3,4,7
in this probelm we have to check two things one is a^2+b^2=c^2
and 2nd is a,b<c<a+b
now 3^2+4^2=7^2
it is not a pythgorean triple
14 6,8,10
6^2+8^2=10^2
100=100
6<10<14
it satisfied both condtion it is pythogorean triple
15. 45^2+20^2=53^2
it not satisfied the condition
16 5.12,13
5^2+12^2=13^2
169=169
5<13<17
satisfied the condition
17. 10,24,26
10^2+24^2=26^2
676=676
satisfied both condition
18 15,20,25
15^2+20^2=25^2
625=625
15<25<35
it is also satisfied the condition and also the pythagorean triple



