By using Kirchhoffs Laws it can be shown that the currents I

By using Kirchhoff\'s Laws, it can be shown that the currents I₁, I₂, and I₃ that pass through the three branches of the circuit in the figure satisfy the given linear system. Solve the system to find I₁, I₂, and I₃. (Round your answers to three decimal places. Assume that R₁ = 16 , R₂ = 8 , R₃ = 4 , V₁ = 7 V, and V₂ = 6 V.) I₁ + I₂+ I₃ =0 16I₁ - 8I₂ =7 8I₂ + 4I₃

=6

Solution

I1 + I2+ I3 =0 ---(1)

16I1 - 8I2 =7 ----(2)

8I2 + 4I3 =6 ----(3)

solve the three equation to get values of I1 , I2 and I3:

we get I1 = 19/8 amp ; I2 =31/8 amp ; I3 = -25/4 amp