Suppose a truebreeding gray colred normal fruit fly was cros
Suppose a true-breeding gray colred (normal) fruit fly was crossed to an ebony colored fruit fly. The allele for gray body is e+ and the allele for ebony body color is e. The F1 generation is then allowed to mate with another. What are the following probabilities for the F2 generation? (make sure to show your Punnet Square and you calculations)
1. The first offspring has an ebony body
2. The first offspring has a gray (normal) body
3. The first offspring is gray, the second offspring is ebony, and the third offspring is ebony.
Solution
Gray color : e+e+
Ebony color :ee
If gary is dominant over ebony color,then
F1 will be all e+e ( all gray color)
F1 mating: e+e * e+e Paternal
If the gray color is dominant over ebony color , then:
1.Probability that the first offspring has an ebony body is : 1/4 = 0.25
2.Probability that the first offspring has a gray(normal) body is:3/4 = 0.75
3.Probability that the first offspring is gray,the second offspring is ebony and third offspring is ebony is:0
| Maternal | e+ | e |
| e+ | e+e+ gray | e+e gray |
| e | e+e gray | ee ebony |
