The critical F value with 8 numerator and 6 denominator degr

The critical F value with 8 numerator and 6 denominator degrees of freedom at = .05 is: a. 4.88 b. None of these choices are correct. c. 4.15 d. 3.58

For this problem where and when does the alpha come in? And how does it have to do with the chart?

Solution

the critical F value with numerator df 8 and denominator df 6 at alpha=0.05

is F_0.05,8,6=that value of F under which 95% of the total probability exists=4.15 [option c]   [using minitab]

for this problem alpha is the value of level of significance. alpha=0.05 means that we are to find that critical point above which 5% of the total probability exists which means under which 95% of the total probability exists.