where R 02 X 03Solutionx varies from 0 to 2 Hence if m4 4 s

where R = (0,2) X (0,3)

Solution

x varies from 0 to 2.

Hence if m=4, 4 subdivisions would be at x = 0, 0.5, 1, 1.5, 2

Midpoints would be x = 0.25, 0.75, 1.25, 1.75

Similarly for y, y = 0,1,2,3

Mid points =0.5, 1.5, 2.5

Hence answer is 34.875

y/x 0.25 0.75 1.25 1.75
0.5 1.5625 2.0625 3.0625 4.5625 11.25
1.5 4.5625 5.0625 6.0625 7.5625 23.25
2.5 7.5625 8.0625 9.0625 10.5625 35.25
13.6875 15.1875 18.1875 22.6875 69.75
Area of each cell = 0.5(1) 0.5
Integral value 69.75(0.5)
34.875
where R = (0,2) X (0,3)Solutionx varies from 0 to 2. Hence if m=4, 4 subdivisions would be at x = 0, 0.5, 1, 1.5, 2 Midpoints would be x = 0.25, 0.75, 1.25, 1.7

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