Suppose two fair dice plural are rolled Find the given proba
Suppose two fair dice (plural) are rolled. Find the given probabilities.
a) The sum is 5 or the second die shows a 3
b) Both dice show the same number, or the sum is at least 11.
Solution
Two dice are rolled
Sample space will consist of 36 elements
a) Prob for sum is 5 or Second die shows a 3
Let A = sum is 5
Fvle outcomes for A = (1,4) (2,3) (3,2( 4,1) = 4
Favourable for AB = (2,3) =1
Second die shows a 3 prob = 1/6
P(A) = 4/36
P(B)=6/36
P(AB) = 1/36
Hence Prob (sum is 5 or second die shows a 3) = P(AUB) = P(A)+P(B)_P(AB)
= 9/36 =0.25
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b) Let C = both die show the same number
D= sum is atleast 11
Favourable outcomes for C = (1,1)(2,2)...(6,6)
FAvourable outcomes for D= (5,6) (6,5) (6,6)
For both = (6,6)
Hence P(CUD) = P(C)+P(D)-P(CD)
= (6+3-1)/36 = 0.2222
