Solve the following system of linear equations Write you ans

Solve the following system of linear equations. Write you answer in parametric form.

x1 + 2x2   + x4 =3

3x1 + 6x2 + 6x3 + 21x4 6x5   =-9

x1 + 2x2 + x3 + 4x4 + x5 =0

4x1 + 8x2 + 6x3 + 22x4 6x5 =6

Solution

IF WE solve:

x1 + 2x2   + x4 =3

3x1 + 6x2 + 6x3 + 21x4 6x5   =-9

x1 + 2x2 + x3 + 4x4 + x5 =0

4x1 + 8x2 + 6x3 + 22x4 6x5 =6

equations we will get 3equations

     3x1+2x2-x3+6x5=12

    3x1+6x2-x3-x5=12

   3x1+6x2-x3+x5=12

   and solve this and got

can be transformed by a sequence of elementary row operations to the matrix

The reduced row echelon form of the augmented matrix is

which corresponds to the system

No equation of this system has a form zero = nonzero; Therefore, the system is consistent.

The leading entries in the matrix have been highlighted in yellow.

A leading entry on the (i,j) position indicates that the j-th unknown will be determined using the i-th equation.

Those columns in the coefficient part of the matrix that do not contain leading entries, correspond to unknowns that will be arbitrary. The system has infinitely many solutions:

i,e x4=x5.

then x4=3-x1-2x2

Step 1: Transform the augmented matrix to the reduced row echelon form  (Show details)
Solve the following system of linear equations. Write you answer in parametric form. x1 + 2x2 + x4 =3 3x1 + 6x2 + 6x3 + 21x4 6x5 =-9 x1 + 2x2 + x3 + 4x4 + x5 =0

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