Find the angle between the vectors 6 4 and 6 5 Carry your in

Find the angle between the vectors (-6, -4) and (-6, 5). Carry your intermediate computations to at least 4 decimal places. Round your final answer to the nearest degree.

Solution

Vectors are (-6,-4),(-6,-5)

Let u=(-6,-4) and   v= (-6,5)

u.v= -6* -6+ -4*5 = 16

I u I=sqrt(36 +16)= sqrt52

I v I= sqrt(36+25)= sqrt61

I u I I v I=sqrt 52 *sqrt61= 56.3205

cos theta=u.v/I u I I v I

cos theta=16/56.3205

theta=cos^-1(16/56.3205) = 73.5 degree