air conditioning principles steps please A more delailed dis
air conditioning principles
 steps please
Solution
A) Area of roof top = 120*80 = 9600ft2 = 1.3824*106 in2
Thermal conductivity of R-5.5 = KR-5.5 = 0.00217 Btu/in h oF
Thermal conductivity of Wood = Kw = 0.00816 Btu/in h oF
Let us consider thickness of insulation =x1 = 1 inch
According to Fourier\'s law of heat conduction,
Q = [A*(To - Ti)]/[(x1/ KR-5.5)+(x2/Kw)]
To = 87.8oF .......(Ambient temperature at noon on september 21)
Ti = 78 oF
So, net roof coolin load, Q = 23222.521 Btu.
B) Time of peak roof heat gain is from noon to 5 pm.

