Homework SourseIf the random variable z is the standard normal score then z
| If the random variable z is the standard normal score, then z(0.2611) is equal to |
| If the random variable z is the standard normal score, then z(0.2611) is equal to |
Solution
z-score for 0.2611 is -0.64. That is area left to the z-score -0.64 is .2611 from standard normal distibution table (z-table).
