The table below shows the critical reading scores for 14 stu
The table below shows the critical reading scores for 14 students the first two times they took a standardized test. At a=0.01, is there enough evidence to conclude that their scores improved the second time they took the test?
        1st      2nd
 1      334   337
 2      476   506
 3      489   506
 4      367   392
 5      503   464
 6      389   430
 7      586   533
 8      463   483
 9      566   578
 10   547   564
 11   543   581
 12   370   405
 13   420   455
 14   545   574
1. Identify the claim and state H0 and Ha
2. Find the critical values & identify the rejection regions.
3. Calculate d and sd
4. Use the t-test to find the standardized the test statistic t
5. Decide whether to reject or fail to reject the null hypothesis
Solution
Let mu1 and mu2 represent the scores of students between the first and second time.
H0: mu1 = mu2
Ha: mu1<mu2
Left tailed test.
Difference Scores Calculations
 
 Mean: 15
  = 0
 S2 = SSdf = 10252(14-1) = 788.62
 S2M = S2N = 788.6214 = 56.33
 SM = S2M = 56.33 = 7.51
 
 T-value Calculation
 
 t = (M - )SM = (15 - 0)7.51 = 2.00
p = 0.9666
As p value is high, accept null hypothesis
There is no improvement as per statistical tests.

