solve sin2theta51Solutionsin 25 1 25 sin1 1 25 2n 2 2

solve sin2theta/5=-1

sin (2/5) = -1

==> 2/5 = sin^-1 (-1)

==> 2/5 = (2n - /2) , (2n + 3/2) ; n belongs to integers

==> 2/5 = (1/2) (4n - ) , (1/2)(4n + 3)

==> = (5/4) (4n - ) , (5/4)(4n + 3)

Hence solution to sin (2/5) = -1 is (5/4) (4n - ) , (5/4)(4n + 3) , n belongs to integers