If sin theta 45 and cos theta 0 find sin 2 theta cos 2 the

If sin theta = -4/5 and cos theta > 0, find sin (2 theta), cos (2 theta), and tan (2 theta).

sin theta= -(4/5)

here opposite= -4 and hypotenuse=5

therefore adjacent= sqrt( 25-16)=3

cos theta= adjacent/hypotenuse

Therefore cos theta=(3/5)

sin2 theta= 2sin theta cos theta=2(-4/5)(3/5)=-24/25

cos 2theta=cos^2 theta-sin^2 theta= (3/5)^2 -(-4/5)^2=9/25-16/25=-7/25

Tan 2theta=sin 2theta/cos2theta=-24/25/-7/25=(24/7)