Using Linear Differentiation how do you solve y4y12y0Solutio

Using Linear Differentiation how do you solve y\'\'-4y\'-12y=0?

Solution

We have:

y\'\'-4y\'-12y=0

Therefore:

D^2 y - 4D y - 12y = 0

(D^2 - 4D - 12)y = 0

D^2 - 4D - 12 = 0

(D-6)(D+2) = 0

So the roots are: D = -2 , 6

Thus the solution is:

y = Ae^(-2x) + Be^(6x)

where A and B are constants.

Using Linear Differentiation how do you solve y\'\'-4y\'-12y=0?SolutionWe have: y\'\'-4y\'-12y=0 Therefore: D^2 y - 4D y - 12y = 0 (D^2 - 4D - 12)y = 0 D^2 - 4D

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