Using Linear Differentiation how do you solve y4y12y0Solutio
Using Linear Differentiation how do you solve y\'\'-4y\'-12y=0?
Solution
We have:
y\'\'-4y\'-12y=0
Therefore:
D^2 y - 4D y - 12y = 0
(D^2 - 4D - 12)y = 0
D^2 - 4D - 12 = 0
(D-6)(D+2) = 0
So the roots are: D = -2 , 6
Thus the solution is:
y = Ae^(-2x) + Be^(6x)
where A and B are constants.
