Find all triangles with A 431 degree a 1862 and b 2486 if

Find all triangles with A = 43.1 degree, a = 186.2, and b = 248.6 if any such exist. Round each part, of your answer to the nearest tenth.

Solution

A = 43.1

a = 186.2

b = 248.6

Now law of cosines: a/sinA = b/sinB

186.2/sin43.1 = 248.6/sinB

B = 65.82

now the third angle =C = 180 - 43.1- 65.82 = 71.08

Now, c = sqrt[]a^2+ b^2 -2abcosC] = 355.66