public String countHelloint count returns a string that cont

public String countHello(int count) returns a string that contains Hello count times all on one line, separated by spaces. You must use a loop. The output for countHello(5) will look like this:

Hello Hello Hello Hello Hello

public int sumEveryThird(int limit) finds the sum of every third number that is less than a given number starting with 3 - EXCEPT those divisible by 5. Use loop. If the limit is 21, you would calculate

3 + 6 + 9 + 12 + 18 = 48
and the method would return 48

public String noXYZ(String s) returns a string in which all the letters x, y, and z have been removed. You must use a loop.

Solution

//java code

public class Driver
{
   public static String countHello(int count)
   {
      String result = \"\";
      for (int i = 0; i < count ;i++ )
      {
          result = result + \"Hello \";   
      }

      return result;
   }

   public static int sumEveryThird(int limit)
   {
      int sum = 0;
      for (int i = 3; i < limit ; i=i+3 )
      {
          if (i%5 != 0)
          {
              sum = sum + i;      
          }  
      }

      return sum;
   }

   public static String noXYZ(String s)
   {
      s = s.replace(\"x\", \"\");
      s = s.replace(\"y\", \"\");
      s = s.replace(\"z\", \"\");

      s = s.replace(\"X\", \"\");
      s = s.replace(\"Y\", \"\");
      s = s.replace(\"Z\", \"\");

      return s;

   }
   public static void main(String[] args)
   {

        System.out.println(countHello(6));
        // output: Hello Hello Hello Hello Hello Hello

        System.out.println(\"Sum: \" + sumEveryThird(21));
        // output: Sum: 48

        System.out.println(noXYZ(\"my name is xyz, I am from XYZ placeZZ\"));
        // output: m name is , I am from place

     }
}