Consider the loop including the 6 and 12 Ohm resistors Which

Consider the loop including the 6 and 12 Ohm resistors. Which of the following is correct? 13 (6.00 Ohm)+14 (12.00 Ohm)=0 13 (6.00 Ohm) minus 14 (12.00 Ohm)=0 12 +13 (6.00 Ohm)+14 (12.00 Ohm)=0 none of the above

Solution

(B) as we can see that potential across 6 ohm and 12 ohm resistors are equal.

I₃(6)=I₄(12)

I₃(6)-I₄(12)=0