can someone please solve 1920 Two sides of a triangle have l

can someone please solve 19-20
Two sides of a triangle have lengths 7 inches and 12 inches. Their included angle measure 99 degree. Find the area of the triangle. Find the area of a triangle with sides 30 meters, 41 meters, and 45 meters. Write the vector u = (7, 8) as a linear combination of the standard unit vector i and j. Given: u = 1, 7 v = -6, 5 Compute. u+v u-v 5u-3v 4u+2v Find a unit vector in the direction of u = (24, -7). Write the complex number 6 - squareroot-49 in standard form. Perform the operation & write the result in standard form. 6i - (2 + aquareroot-81 (squareroot3 + i)(squareroot3 - i))5i - 2)^2 8i/10 + 2i Identify the conic, write in standard form then graph the section on the graph paper (provided here): 9x^2 + 4y^3 - 36x + 8y + 4 = 0 4x^2 - y^2 - 4 = 0 x^2 + y^2 + 2x - 6y -12 = 0 y^2 + 2x + 2 = 0 6e^2x = 72 log_2 x + log_2 5 = 6 4^x - 5 + 21 = 30 ln 4x - ln 2 = 8 Condense: 2 ln x - 1/2 ln(x + 5) Expand: ln(x^2 - 16/x^4)

Solution

19)a=7,b=12,C=99o

area of triangle =(1/2)ab sinC

area of triangle =(1/2)7*12* sin99o

area of triangle =41.5 square inches

20)a=30,b =41 ,c =45

s=(a+b+c)/2=(30+41+45)/2=58

area of triangle =[s(s-a)(s-b)(s-c)]

area of triangle =[58(58-30)(58-41)(58-45)]

area of triangle =599 square meters

can someone please solve 19-20 Two sides of a triangle have lengths 7 inches and 12 inches. Their included angle measure 99 degree. Find the area of the triangl

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