What is the expected phenotype ratio of the PPSs x Ppss cros
What is the expected phenotype ratio of the PPSs x Ppss cross described in the previous question? Write the ratio in the order of # purple smooth, # purple constricted, # white smooth, # white constricted. Use the format as in the following example: 2:2:1:0 (integers separated by colons with no spaces; be sure to type zero and not the letter O if the phenotype is expected to be absent; also the ratio must be reduced).
Solution
Answer
Allele for character for Purple is P
Allele for character for White is p
Allele for character for Smooth is S
Allele for character for constricted is s
The combination of these alleles will be
Purple smooth PPSS, PpSs
Purple constricted PPss, Ppss
White smooth ppSS, ppSs
White constricted ppss
Parents P1 PPSs x Ppss
Gamets PS PS Ps Ps Ps Ps ps ps
Cross
Ps
Ps
ps
ps
PS
PPSs
PPSs
PpSs
PpSs
PS
PPSs
PPSs
PpSs
PpSs
Ps
PPss
PPss
ppss
ppss
Ps
PPss
PPss
ppss
ppss
Number of purple and smooth will be 8
Number of purple and constricted will be 4
Number of white and smooth will be 0 (zero)
Number of white and constricted will be 4
Therefore, the phenotypic ratio of purple smooth, purple constricted, white smooth, white constricted will be 8:4:0:4
| Cross | Ps | Ps | ps | ps |
| PS | PPSs | PPSs | PpSs | PpSs |
| PS | PPSs | PPSs | PpSs | PpSs |
| Ps | PPss | PPss | ppss | ppss |
| Ps | PPss | PPss | ppss | ppss |

