Question 2 20 points total Write the body of the method prin

Question 2. 20 points total

Write the body of the method printAllButOmitted. The method signature is provided.
The method is passed an array of names, inputNames, and a name NOT to print, omittedName. Names are represented by String objects.
Your code MUST print all of the names contained in the array inputNames except the omittedName.

Example 1: Suppose inputNames and omittedName have the following values:

omittedName was assigned to \"Jill\"
inputNames contained the names \"Pinar\",\"Yanjie\",\"Ryan\",\"Francis\",\"Jill\",\"Janet\", \"Jill\"


Your code should print (without any errors):

Pinar Yanjie Ryan Francis Janet

Note that all occurrences of the omitted name are not printed.

Example 2: Suppose inputNames and omittedName have the following values:

omittedName was assigned to \"Jill\"
inputNames contained the names \"Pinar\",\"Yanjie\",\"Ryan\",\"Francis\",\"Jill\",\"Janet\", \"Jill\", \"Pinar\"


Your code should print (without any errors):

Pinar Yanjie Ryan Francis Janet Pinar

Note that \"Pinar\" was printed twice because that name occurred twice in the array.

Important conditions:

The names MUST be printed in one line with a space between them.

Assume that the array inputNames has length > 0.

Assume that omittedName has been assigned to a name.

Do not be concerned with upper or lower case. Assume all names begin with a capital letter.

If the omitted name appears more than once all instances are omitted in the output(see examples above).

All names in the array that are not the omitted name are printed. If a name occurs more than once it will be printed as many times as it occurs(see example 2 above).

Remember, your code must work for any names (possibly zero) that inputNames contains, and for any name omittedName might be assigned to, not just the example given above.

Write the body of the method printAllButOmitted. The method signature is provided. The method is passed an array of names, inputNames, and a name NOT to print, omittedName. Names are represented by String objects. Your code MUST print all of the names contained in the array inputNames except the omittedName. Example 1: Suppose inputNames and omittedName have the following values: omittedName was assigned to \"Jill\" inputNames contained the names \"Pinar\", \"Yanjie\", \"Ryan\", \"Francis\", \"Jill\", \"Janet\", \"Jill\" Your code should print (without any errors): Pinar Yanjie Ryan Francis Janet Note that all occurrences of the omitted name are not printed. Example 2: Suppose inputNames and omittedName have the following values: omittedName was assigned to \"Jill\" inputNames contained the names \"Pinar\", \"Yanjie\", \"Ryan\", \"Francis\", \"Jill\", \"Janet\", \"Jill\", \"Pinar\" Your code should print (without any errors): Pinar Yanjie Ryan Francis Janet Pinar Note that \"Pinar\" was printed twice because that name occurred twice in the array. Important conditions: The names MUST be printed in one line with a space between them. Assume that the array inputNames has length > 0. Assume that omittedName has been assigned to a name. Do not be concerned with upper or lower case. Assume all names begin with a capital letter. If the omitted name appears more than once all instances are omitted in the output(see examples above). All names in the array that are not the omitted name are printed. If a name occurs more than once it will be printed as many times as it occurs(see example 2 above). Remember, your code must work for any names (possibly zero) that inputNames contains, and for any name omittedName might be assigned to, not just the example given above.

Solution

public void printAllButOmitted(String[] inputNames,String omittedName)

{

if(inputNames.length()>0)

{

String name=omittedName;

for(int i=0;i<inputNames.length;i++)

{

if(!(inputNames[i].equalsIgnoreCase(name)))

System.out.print(\"\\\"\"+inputNames[i]+\"\\\"\"+\"\\t\");

}

}

else System.out.println(\" \");

}